If f(x)=ax2+bx+cf(x) = ax^2 + bx + cf(x)=ax2+bx+c and f(0)=5f(0) = 5f(0)=5, what do we know about the coefficients?
a=5a=5a=5
b=5b=5b=5
c=5c=5c=5
a+b+c=5a+b+c=5a+b+c=5