If f(x)=4x−3f(x) = 4^{x-3}f(x)=4x−3, what is f−1(x)f^{-1}(x)f−1(x)?
f−1(x)=log4(x)−3f^{-1}(x) = \log_4(x) - 3f−1(x)=log4(x)−3
f−1(x)=log4(x)+3f^{-1}(x) = \log_4(x) + 3f−1(x)=log4(x)+3
f−1(x)=log4(x+3)f^{-1}(x) = \log_4(x+3)f−1(x)=log4(x+3)
f−1(x)=4x+3f^{-1}(x) = 4^{x} + 3f−1(x)=4x+3