If f(x)=4−x2f(x) = 4 - x^2f(x)=4−x2 for x≥0x \ge 0x≥0, find f−1(x)f^{-1}(x)f−1(x).
f−1(x)=4−xf^{-1}(x) = \sqrt{4-x}f−1(x)=4−x
f−1(x)=4−xf^{-1}(x) = 4 - \sqrt{x}f−1(x)=4−x
f−1(x)=x2−4f^{-1}(x) = x^2 - 4f−1(x)=x2−4
f−1(x)=x−4f^{-1}(x) = \sqrt{x} - 4f−1(x)=x−4