If f(x)=2x+1f(x) = 2x+1f(x)=2x+1 and g(x)=x2g(x) = x^2g(x)=x2, which statement is true about (f∘g)(x)(f \circ g)(x)(f∘g)(x)?
(f∘g)(x)=2x2+1(f \circ g)(x) = 2x^2+1(f∘g)(x)=2x2+1
(f∘g)(x)=(2x+1)2(f \circ g)(x) = (2x+1)^2(f∘g)(x)=(2x+1)2
(f∘g)(x)=4x2+1(f \circ g)(x) = 4x^2+1(f∘g)(x)=4x2+1
(f∘g)(x)=2x2+2(f \circ g)(x) = 2x^2+2(f∘g)(x)=2x2+2