If f(x)=2x+1f(x) = 2x+1f(x)=2x+1 and g(x)=x−12g(x) = \frac{x-1}{2}g(x)=2x−1, are these functions inverses?
Yes
No, they are identical
No, f(g(x))=x+1f(g(x)) = x+1f(g(x))=x+1
No, g(f(x))=2x−1g(f(x)) = 2x-1g(f(x))=2x−1