If f(x)=2x−7f(x) = 2x-7f(x)=2x−7 and g(f(x))=6x−1g(f(x)) = 6x-1g(f(x))=6x−1, what is g(x)g(x)g(x)?
g(x)=3x+20g(x) = 3x+20g(x)=3x+20
g(x)=3x−1g(x) = 3x-1g(x)=3x−1
g(x)=6x+2g(x) = 6x+2g(x)=6x+2
g(x)=2x+1g(x) = 2x+1g(x)=2x+1