If dydx=f(x)\frac{dy}{dx} = f(x)dxdy=f(x), what does this imply about the solution y(x)y(x)y(x)?
y(x)=f′(x)+Cy(x) = f'(x) + Cy(x)=f′(x)+C
y(x)=∫f(x)dx+Cy(x) = \int f(x) dx + Cy(x)=∫f(x)dx+C
y(x)=f(x)+Cy(x) = f(x) + Cy(x)=f(x)+C
y(x)=C⋅f(x)y(x) = C \cdot f(x)y(x)=C⋅f(x)