If f(g(x))=x2+1f(g(x)) = x^2 + 1f(g(x))=x2+1 and f(x)=x+1f(x) = x+1f(x)=x+1, what is g(x)g(x)g(x)?
x2x^2x2
x2+1x^2+1x2+1
x2−1x^2-1x2−1
x+1x+1x+1