If cos(θ)=x\cos(\theta) = xcos(θ)=x, which of the following is equivalent to sin2(θ)\sin^2(\theta)sin2(θ)?
1−x21 - x^21−x2
1+x21 + x^21+x2
x2−1x^2 - 1x2−1
1−x2\sqrt{1 - x^2}1−x2