If A(x)=∑n=0∞anxn=1(1−x)2A(x) = \sum_{n=0}^{\infty} a_n x^n = \frac{1}{(1-x)^2}A(x)=∑n=0∞anxn=(1−x)21, what is ana_nan?
nnn
n+1n+1n+1
n2n^2n2
2n2^n2n