If Ax=bAx = bAx=b and Ay=bAy = bAy=b are two distinct solutions, what can be said about A(x−y)A(x-y)A(x−y)?
A(x−y)=bA(x-y) = bA(x−y)=b
A(x−y)=0A(x-y) = 0A(x−y)=0
A(x−y)=2bA(x-y) = 2bA(x−y)=2b
A(x−y)=−bA(x-y) = -bA(x−y)=−b