If α+β+γ=π\alpha + \beta + \gamma = \piα+β+γ=π, which of the following is equal to sin(2α)+sin(2β)+sin(2γ)\sin(2\alpha) + \sin(2\beta) + \sin(2\gamma)sin(2α)+sin(2β)+sin(2γ)?
4sinαsinβsinγ4\sin \alpha \sin \beta \sin \gamma4sinαsinβsinγ
2cosαcosβcosγ2\cos \alpha \cos \beta \cos \gamma2cosαcosβcosγ
4cosαcosβcosγ4\cos \alpha \cos \beta \cos \gamma4cosαcosβcosγ
sinαsinβsinγ\sin \alpha \sin \beta \sin \gammasinαsinβsinγ