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Recursion
easy
0:00.0
If
a
n
=
a
n
−
1
a_n = \sqrt{a_{n-1}}
a
n
=
a
n
−
1
and
a
0
=
16
a_0 = 16
a
0
=
16
, what is
a
2
a_2
a
2
?
A
4
B
2
C
\sqrt{2}
D
1
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