If an=an−1+an−2a_n = a_{n-1} + a_{n-2}an=an−1+an−2 with a0=0,a1=1a_0=0, a_1=1a0=0,a1=1, what is the identity for ∑i=0nai2\sum_{i=0}^n a_i^2∑i=0nai2?
an2a_n^2an2
anan+1a_n a_{n+1}anan+1
an+12−1a_{n+1}^2 - 1an+12−1
anan−1+1a_n a_{n-1} + 1anan−1+1