If an=2na_n = 2^nan=2n is a solution for an=c1an−1+c2an−2a_n = c_1 a_{n-1} + c_2 a_{n-2}an=c1an−1+c2an−2, which equation is satisfied by c1,c2c_1, c_2c1,c2?
4=2c1+c24 = 2c_1 + c_24=2c1+c2
1=2c1+4c21 = 2c_1 + 4c_21=2c1+4c2
c1+2c2=4c_1 + 2c_2 = 4c1+2c2=4