If a triangle has vertices at (0,0),(a,0),(0,0), (a,0),(0,0),(a,0), and (0,b)(0,b)(0,b), the orthocenter is located at:
(a3,b3)(\frac{a}{3}, \frac{b}{3})(3a,3b)
(0,0)(0,0)(0,0)
(aba+b,aba+b)(\frac{ab}{a+b}, \frac{ab}{a+b})(a+bab,a+bab)
None of the above