If a recursive function f(n)f(n)f(n) is defined as f(n)=f(n−2)+nf(n) = f(n-2) + nf(n)=f(n−2)+n, with f(0)=0f(0) = 0f(0)=0 and f(1)=1f(1) = 1f(1)=1, what is f(4)f(4)f(4)?
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