If A=PDP−1A = PDP^{-1}A=PDP−1 where D=(2003)D = \begin{pmatrix} 2 & 0 \\ 0 & 3 \end{pmatrix}D=(2003), what is A4A^4A4?
P(160081)P−1P\begin{pmatrix} 16 & 0 \\ 0 & 81 \end{pmatrix}P^{-1}P(160081)P−1
P(80012)P−1P\begin{pmatrix} 8 & 0 \\ 0 & 12 \end{pmatrix}P^{-1}P(80012)P−1
(160081)\begin{pmatrix} 16 & 0 \\ 0 & 81 \end{pmatrix}(160081)
Cannot be determined without knowing PPP