If a parabola is defined by y=4(x−1)2+2y = 4(x-1)^2 + 2y=4(x−1)2+2, what is the vertex?
(−1,2)(-1, 2)(−1,2)
(1,2)(1, 2)(1,2)
(1,−2)(1, -2)(1,−2)
(2,1)(2, 1)(2,1)