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Recursionhard
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If a function is defined as f(n)=f(n−1)+f(n−2)+⋯+f(0)f(n) = f(n-1) + f(n-2) + \dots + f(0)f(n)=f(n−1)+f(n−2)+⋯+f(0) with f(0)=1f(0)=1f(0)=1, what is f(3)f(3)f(3)?