If a force F(x)=3x2+1F(x) = 3x^2 + 1F(x)=3x2+1 acts on an object, the work done from x=0x=0x=0 to x=2x=2x=2 is given by:
∫02(3x2+1)dx\int_0^2 (3x^2 + 1) dx∫02(3x2+1)dx
∫02(x3+x)dx\int_0^2 (x^3 + x) dx∫02(x3+x)dx
F′(2)−F′(0)F'(2) - F'(0)F′(2)−F′(0)
F(2)+F(0)F(2) + F(0)F(2)+F(0)