If a≡2(mod7)a \equiv 2 \pmod{7}a≡2(mod7) and b≡5(mod7)b \equiv 5 \pmod{7}b≡5(mod7), what is (2a+3b) mod 7(2a + 3b) \bmod 7(2a+3b)mod7?
0
3
5
6