If a circle x2+y2=r2x^2 + y^2 = r^2x2+y2=r2 is orthogonal to (x−2)2+y2=1(x-2)^2 + y^2 = 1(x−2)2+y2=1, what is rrr?
111
2\sqrt{2}2
3\sqrt{3}3
222