If A=(1102)A = \begin{pmatrix} 1 & 1 \\ 0 & 2 \end{pmatrix}A=(1012), find the matrix PPP such that P−1AP=DP^{-1}AP = DP−1AP=D.
(1101)\begin{pmatrix} 1 & 1 \\ 0 & 1 \end{pmatrix}(1011)
(1011)\begin{pmatrix} 1 & 0 \\ 1 & 1 \end{pmatrix}(1101)
(1211)\begin{pmatrix} 1 & 2 \\ 1 & 1 \end{pmatrix}(1121)
(2111)\begin{pmatrix} 2 & 1 \\ 1 & 1 \end{pmatrix}(2111)