If a,b,ca, b, ca,b,c are real and a+b+c=0a+b+c=0a+b+c=0, prove that a3+b3+c3=3abca^3+b^3+c^3=3abca3+b3+c3=3abc. Given this, evaluate 23+33+(−5)32^3+3^3+(-5)^323+33+(−5)3.
−90-90−90
909090
000
−30-30−30