If AAA and BBB are independent, prove P(A∪B)=1−P(Ac)P(Bc)P(A \cup B) = 1 - P(A^c)P(B^c)P(A∪B)=1−P(Ac)P(Bc). Which is the numerical equivalent if P(A)=0.5,P(B)=0.6P(A)=0.5, P(B)=0.6P(A)=0.5,P(B)=0.6?
0.80.80.8
0.30.30.3
0.70.70.7
0.90.90.9