Ononot — If a 2 \times 2 matrix A has eigenvalues \lambda1 = 3 and \l

Eigenvalues & Eigenvectorseasy

0:00.0

If a $2 \times 2$ matrix $A$ has eigenvalues $\lambda_1 = 3$ and $\lambda_2 = 3$ , and is NOT diagonalizable, what is the dimension of the eigenspace corresponding to $\lambda = 3$ ?