Identify the Maclaurin series for f(x)=14+x2f(x) = \frac{1}{4+x^2}f(x)=4+x21.
∑n=0∞(−1)nx2n4n+1\sum_{n=0}^{\infty} (-1)^n \frac{x^{2n}}{4^{n+1}}∑n=0∞(−1)n4n+1x2n
∑n=0∞x2n4n\sum_{n=0}^{\infty} \frac{x^{2n}}{4^n}∑n=0∞4nx2n
∑n=0∞(−1)nxn4n\sum_{n=0}^{\infty} (-1)^n \frac{x^n}{4^n}∑n=0∞(−1)n4nxn
∑n=0∞x2n+14n+1\sum_{n=0}^{\infty} \frac{x^{2n+1}}{4^{n+1}}∑n=0∞4n+1x2n+1