Identify the integrating factor μ(x)\mu(x)μ(x) for the linear first-order ODE: y′+6y=e2xy' + 6y = e^{2x}y′+6y=e2x.
μ(x)=e6x\mu(x) = e^{6x}μ(x)=e6x
μ(x)=6x\mu(x) = 6xμ(x)=6x
μ(x)=ex\mu(x) = e^xμ(x)=ex
μ(x)=e−6x\mu(x) = e^{-6x}μ(x)=e−6x