Identify the hole in the function f(x)=x2−4x+3x2−1f(x) = \frac{x^2 - 4x + 3}{x^2 - 1}f(x)=x2−1x2−4x+3.
x=1x = 1x=1
x=−1x = -1x=−1
x=3x = 3x=3
No hole