Identify the hole for f(x)=x2−4x+3x2−1f(x) = \frac{x^2-4x+3}{x^2-1}f(x)=x2−1x2−4x+3
x=1x=1x=1
x=−1x=-1x=−1
x=3x=3x=3
x=−3x=-3x=−3