Identify the general solution to the differential equation y′=xy' = xy′=x.
y=x2+Cy = x^2 + Cy=x2+C
y=12x2+Cy = \frac{1}{2}x^2 + Cy=21x2+C
y=1+Cy = 1 + Cy=1+C
y=x+Cy = x + Cy=x+C