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Random Variableseasy
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Given XXX has PDF f(x)=12f(x) = \frac{1}{2}f(x)=21​ for x∈[0,2]x \in [0, 2]x∈[0,2], what is the median mmm such that P(X≤m)=0.5P(X \leq m) = 0.5P(X≤m)=0.5?