Given the scalar k=3k = 3k=3 and matrix B=(02−14)B = \begin{pmatrix} 0 & 2 \\ -1 & 4 \end{pmatrix}B=(0−124), what is the scalar product kBkBkB?
(06−312)\begin{pmatrix} 0 & 6 \\ -3 & 12 \end{pmatrix}(0−3612)
(3527)\begin{pmatrix} 3 & 5 \\ 2 & 7 \end{pmatrix}(3257)
(0527)\begin{pmatrix} 0 & 5 \\ 2 & 7 \end{pmatrix}(0257)
(06−14)\begin{pmatrix} 0 & 6 \\ -1 & 4 \end{pmatrix}(0−164)