Given the recurrence an=6an−1−9an−2a_n = 6a_{n-1} - 9a_{n-2}an=6an−1−9an−2 with a0=1,a1=3a_0 = 1, a_1 = 3a0=1,a1=3, find a2a_2a2.
000
999
181818
272727