Given the recurrence an=2an−1+3an−2a_n = 2a_{n-1} + 3a_{n-2}an=2an−1+3an−2 with initial conditions a0=1a_0 = 1a0=1 and a1=1a_1 = 1a1=1, find a2a_2a2.
555
444
333
666