Given the function f(n)=n2+n+41f(n) = n^2 + n + 41f(n)=n2+n+41. For which values of nnn is f(n)f(n)f(n) composite?
n=40n = 40n=40
n=41n = 41n=41
n=1n = 1n=1
n=0n = 0n=0