Given the characteristic roots r1=1,r2=2,r3=3r_1 = 1, r_2 = 2, r_3 = 3r1=1,r2=2,r3=3, what is the recurrence relation?
an=6an−1−11an−2+6an−3a_n = 6a_{n-1} - 11a_{n-2} + 6a_{n-3}an=6an−1−11an−2+6an−3
an=3an−1−2an−2+an−3a_n = 3a_{n-1} - 2a_{n-2} + a_{n-3}an=3an−1−2an−2+an−3
an=6an−1+11an−2+6an−3a_n = 6a_{n-1} + 11a_{n-2} + 6a_{n-3}an=6an−1+11an−2+6an−3
an=−6an−1+11an−2−6an−3a_n = -6a_{n-1} + 11a_{n-2} - 6a_{n-3}an=−6an−1+11an−2−6an−3