Given that ∑n=1∞1n2\sum_{n=1}^{\infty} \frac{1}{n^2}∑n=1∞n21 converges, which series must converge by the comparison test?
∑n=1∞12n2\sum_{n=1}^{\infty} \frac{1}{2n^2}∑n=1∞2n21
∑n=1∞1n2+1\sum_{n=1}^{\infty} \frac{1}{n^2+1}∑n=1∞n2+11
∑n=1∞∣cosn∣n2\sum_{n=1}^{\infty} \frac{|\cos n|}{n^2}∑n=1∞n2∣cosn∣
All of the above