Given that A={x∈R:x2−1≤0}A = \{x \in \mathbb{R} : x^2 - 1 \leq 0\}A={x∈R:x2−1≤0} and B={x∈R:x2−4x+3≤0}B = \{x \in \mathbb{R} : x^2 - 4x + 3 \leq 0\}B={x∈R:x2−4x+3≤0}, find A∪BA \cup BA∪B.
[−1,3][-1, 3][−1,3]
[1,3][1, 3][1,3]
[−1,1]∪[3,3][-1, 1] \cup [3, 3][−1,1]∪[3,3]
[0,3][0, 3][0,3]