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Recurrence Relationshard
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Given that a recurrence an=c1an−1+c2an−2a_n = c_1 a_{n-1} + c_2 a_{n-2}an​=c1​an−1​+c2​an−2​ has the general solution an=2⋅3n+3⋅2na_n = 2 \cdot 3^n + 3 \cdot 2^nan​=2⋅3n+3⋅2n find the values of c1c_1c1​ and c2c_2c2​.