Given gcd(a,b)=1\text{gcd}(a, b) = 1gcd(a,b)=1, evaluate gcd(a+b,a2−ab+b2)\text{gcd}(a+b, a^2-ab+b^2)gcd(a+b,a2−ab+b2).
Always 1
1 or 3
Always 3
gcd(a, b)