Given tan(θ)=−34\tan(\theta) = -\frac{3}{4}tan(θ)=−43 and θ\thetaθ is in Quadrant II, find sec(θ)\sec(\theta)sec(θ).
−54-\frac{5}{4}−45
54\frac{5}{4}45
−53-\frac{5}{3}−35
45\frac{4}{5}54