Given ∑(xi−xˉ)(yi−yˉ)=120\sum(x_i-\bar{x})(y_i-\bar{y})=120∑(xi−xˉ)(yi−yˉ)=120, ∑(xi−xˉ)2=40\sum(x_i-\bar{x})^2=40∑(xi−xˉ)2=40, xˉ=3\bar{x}=3xˉ=3, yˉ=12\bar{y}=12yˉ=12, find β^1\hat{\beta}_1β^1 and β^0\hat{\beta}_0β^0.
β^1=3, β^0=3\hat{\beta}_1=3,\ \hat{\beta}_0=3β^1=3, β^0=3
β^1=3, β^0=12\hat{\beta}_1=3,\ \hat{\beta}_0=12β^1=3, β^0=12
β^1=4, β^0=0\hat{\beta}_1=4,\ \hat{\beta}_0=0β^1=4, β^0=0
β^1=3, β^0=9\hat{\beta}_1=3,\ \hat{\beta}_0=9β^1=3, β^0=9