Given P(x)=x3+ax+bP(x) = x^3 + ax + bP(x)=x3+ax+b and P(1)=0P(1)=0P(1)=0, find the condition that P(x)P(x)P(x) has a double root.
a + b = 1
4a^3 + 27b^2 = 0
a = -3, b = 2
a = 3, b = -2