Given P(x)=(x−a)(x−b)(x−c)P(x) = (x-a)(x-b)(x-c)P(x)=(x−a)(x−b)(x−c), what is P′(x)P'(x)P′(x) evaluated at x=ax=ax=a?
(a−b)(a−c)(a-b)(a-c)(a−b)(a−c)
(b−a)(c−a)(b-a)(c-a)(b−a)(c−a)
abcabcabc
000