Given P(X)=0.6P(X) = 0.6P(X)=0.6, P(Y)=0.5P(Y) = 0.5P(Y)=0.5, and P(X∪Y)=0.9P(X \cup Y) = 0.9P(X∪Y)=0.9, are events XXX and YYY independent?
Yes, because P(X∩Y)=P(X)P(Y)P(X \cap Y) = P(X)P(Y)P(X∩Y)=P(X)P(Y)
No, because P(X∩Y)≠P(X)P(Y)P(X \cap Y) \neq P(X)P(Y)P(X∩Y)=P(X)P(Y)
Yes, because P(X∩Y)=0P(X \cap Y) = 0P(X∩Y)=0
Indeterminate