Given P(A∣B)=0.8P(A|B) = 0.8P(A∣B)=0.8, P(A∣Bc)=0.2P(A|B^c) = 0.2P(A∣Bc)=0.2, and P(B)=0.6P(B) = 0.6P(B)=0.6, calculate the total probability P(A)P(A)P(A).
0.56
0.6
0.64
0.8