Given P(A∩B)=0.12P(A \cap B) = 0.12P(A∩B)=0.12 and P(Ac∩B)=0.18P(A^c \cap B) = 0.18P(Ac∩B)=0.18, what is the probability P(B)P(B)P(B)?
0.06
0.24
0.30
0.42