Given P(A)=0.4P(A) = 0.4P(A)=0.4, P(B)=0.5P(B) = 0.5P(B)=0.5, and P(A∩B)=0.2P(A \cap B) = 0.2P(A∩B)=0.2, are AAA and BBB independent?
Yes, because P(A∩B)=P(A)P(B)P(A \cap B) = P(A)P(B)P(A∩B)=P(A)P(B)
No, because P(A∩B)≠P(A)P(B)P(A \cap B) \neq P(A)P(B)P(A∩B)=P(A)P(B)
Yes, because P(A∩B)=P(A)+P(B)P(A \cap B) = P(A) + P(B)P(A∩B)=P(A)+P(B)
No, because P(A∩B)=0P(A \cap B) = 0P(A∩B)=0